Skip to content
  • Start free trial
An original census record

Start a free trial to view

Get access to the original record, as well as a map showing the local area at the time

Household of James Joseph Reilly (born 1872, Cheshire Birkenhead)

1911 Census For England & Wales in Kingston, Surrey

James Joseph Reilly and 6 other people are on this record


Get access to the original record, as well as a map showing the local area at the time

James Joseph Reilly's household

Male

James Joseph

Reilly

Head
Female

Elizabeth

Reilly

Wife
Female

Winifrife Mary

Reilly

Daughter
Female

Agnes

Reilly

Daughter
Female

Cecilia Rita

Reilly

Daughter
Female

Sophia

Willmer

Sister-In-Law
Male

Charles

Willmer

Brother-In-Law
First name(s) James Joseph
Last name Reilly
Relationship Head
Marital status Married
Age 39
Birth year 1872
Birth place Cheshire Birkenhead

Household members (7 people)

First name(s)

Last name

Relationship

Marital status

Age

Birth year

Birth place

Full record

James Joseph

Reilly

Head

Married

39

1872

Cheshire Birkenhead

Elizabeth

Reilly

Wife

Married

39

1872

Lincolnshire Grantham

Winifrife Mary

Reilly

Daughter

-

11

1900

Cheshire Birkenhead

Agnes

Reilly

Daughter

-

9

1902

Surrey Kingston upon Thames

Cecilia Rita

Reilly

Daughter

-

6

1905

Surrey Kingston upon Thames

Sophia

Willmer

Sister-In-Law

Single

33

1878

Lincolnshire Grantham

Charles

Willmer

Brother-In-Law

Single

31

1880

Lincolnshire Grantham

Explore Findmypast's newspaper collections

Explore the 1911 Census and millions of historical records for free with Findmypast. Find out more about the household of James Joseph Reilly in Kingston in 1911, and follow the Reilly family through time in other national records, newspapers and more.

We've found family trees for James Joseph Reilly

We’ve found James Joseph Reilly in 356 family trees. Find out more about James Joseph Reilly's household and view the Reilly family in family trees created by Findmypast members.

Not who you're looking for?